Question
A plane EM wave of frequency $30 \mathrm{MHz}$ travels in free space along the $X$ -direction. The electric field component of the wave at a particular point of space and time $E=6 \mathrm{~V} / \mathrm{m}$ along $Y$ -direction. Its magnetic field component $\mathrm{B}$ at this point would be:(a) $2 \times 10^{-8} \mathrm{~T}$ along $\mathrm{Z}$ -direction(b) $6 \times 10^{-6} \mathrm{~T}$ along X-direction(c) $6 \times 10^{-8} \mathrm{~T}$ along Y-direction(d) $6 \times 10^{-8} \mathrm{~T}$ along $\mathrm{Z}$ -direction
Step 1
Step 1: Given that the electric field component of the wave, $E = 6 \, \text{V/m}$ and the wave is travelling in free space, we know that the speed of light in free space, $c = 3 \times 10^8 \, \text{m/s}$. Show more…
Show all steps
Your feedback will help us improve your experience
Ajay Singhal and 54 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The electric field of a certain plane electromagnetic wave is given by $E_{x}=0 ; E_{y}=0 ; E_{z}=(2.0 \mathrm{~V} / \mathrm{m}) \cos [(\pi \times$ $\left.\left.10^{15} \mathrm{~s}^{-1}\right)(t-x / c)\right]$, with $c=3.0 \times 10^{8} \mathrm{~m} / \mathrm{s}$. The wave is propagating in the positive $x$ direction. Write expressions for the components of the magnetic field of the wave.
A plane electromagnetic wave of frequency $25 \mathrm{MHz}$ travels in free space along the $\mathrm{x}$ direction. At a particular point in space and time $\mathrm{E}^{-}=6.3 \mathrm{j} \wedge \mathrm{Vm}^{-1}$ then $\mathrm{B}^{-}$ at this point is (A) $2.1 \times 10^{-8}$ i $\mathrm{T}$ (B) $2.1 \times 10^{-8} \mathrm{k} \wedge \mathrm{T}$ (C) $1.89 \times 10^{9} \mathrm{k} \wedge \mathrm{T}$ (D) $2.52 \times 10^{-7} \mathrm{k} \wedge \mathrm{T}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD