Question
A plant consumes $60 \mathrm{kW}$ at a power factor of 0.75 lagging from a $240-\mathrm{V} \mathrm{rms} 60-\mathrm{Hz}$ line. Determine the value of the capacitor that when placed in parallel with the load will change the load power factor to 0.9 lagging.
Step 1
The power factor is given as 0.75 lagging, which means the angle is the arccosine of 0.75. This gives us an angle of 41.41 degrees. \[ \theta_{old} = \cos^{-1}(0.75) = 41.41^{\circ} \] Show more…
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