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This is chapter 35.
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Problem number 28, we have a plastic film on the glass to increase the reflection to cool down a car.
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So we have air and then the film, the plastic film, and the glass.
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The index of reflection of glass is, let's see, and the glass is 1 .52.
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Is 1 .7 in air, as you know, it's much lower than these too.
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So let's look at the phase change upon reflection from the upper portion.
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Then we're going to have 180 degrees of pace change, but in lower interface, we don't have any.
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So overall change, phase change, is 180 degrees.
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And we want the constructive interference to have.
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Happen, right? that's what it says in the problem.
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So then our equation is going to be twice the thickness equals n plus one half, lambda in this particular medium.
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So then lambda in vacuum or air divided by n foam is going to give us this lambda.
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So then two t is going to be equal to n plus one half.
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Lambda divided by n film, divide both sides by two.
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Then we have the thickness to be m plus 1 half, lambda knot over to m film...