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A point chargc $+2 Q$ is at the origin and a point charge $-Q$ is located along the $x$ -axis

at $x=d$ as in Figure $\mathrm{P} 15.61$ . Find symbolic expressions for the components of the net

force on a third point charge $+Q$ located along the $y$ -axis at $y=d$

$\frac{\sqrt{2} k Q^{2}}{4 d^{2}} \hat{i}+\frac{(8-\sqrt{2}) k Q^{2}}{4 d^{2}} \hat{j}$

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Numerade Educator

University of Washington

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Hope College

we're following arrangements off Charlie's on positive. Why X this year is the why existing yours? Excesses. You have a charge That is a positive kun and another charge of origin that is a two Q Supposed to cure me here we have a negative Q. This point is called a This is B and this point, you see so the distance between BNC is ah d and B's a Gennady, and this distance will be from using if it across the room, the square root off it too. To find a force of two point A due to be, um, force from point A to you to be this effort, baby, that is ah to K Q squared, divided by the square. This is a working only vertically upward, upward, vertically upward. The force on a due to see is given by K Q squared, divided by two D square. This is at the 45 degrees. Um, this is 45 degrees. The hora gentle force will be This is forced a B and this is force here. Um a C by by sprint off too. This force here is a for Stacy divided by the square root of two in this force will be forced to say See, here you feel it presented almost forces diagram vertically and the horizontal force here will be okay. Horizontal Well, he's gentle. For example, is a K X square divided by two schools off to the square. Ah, similarly work ical force will be article will be okay into to kill square divide by D square minus kills Where two's word off to the square. So this week represented by J and the previous one represented by this one represented by I. So the net force will be the combination off these ones. So this one and this one will just add them together and that will be our net force that force.