00:02
Okay, i'm not going to read you the whole problem here.
00:04
I've written down the problem, information, and question a so far.
00:09
So you can see all the information that we're given here.
00:12
And i'm going to draw a quick diagram here.
00:16
If this is q, i've got f, e, and fg, and t.
00:31
Okay, and i know that my summation of my fy is going to be equal to ma and t minus f e minus f g will equal m a and the charges at rest so that equals zero excuse me and f e can be expressed so i'm going to have t f e can oops minus it'll be i can get that minus q e minus m g equals equals so then qe will equal t minus mg divided t minus mg, and then e will equal t minus mg divided by e.
01:50
Okay, let's stick our values into here then.
01:53
So e will equal 5 .18 newton's minus 0 .210 kilograms, and then we're going to multiply that by 9 .8 meters.
02:08
Per second squared.
02:12
We'll divide that by 0 .34, and let's take that times 10 to the minus 6 to get out of microculems.
02:20
And we'll end up with e equals 9 .2 times 10 to the 6 newton coulams...