00:01
So in order to solve this question, the point charge q1 equals negative 4 and c is at the point x 0 .6 meters and y 0 .8 meters.
00:11
And the second point charge q2 with a positive 6 charge is at the point x 0 .6 and y 0.
00:22
And y is 0.
00:24
Calculate the magnitude and direction of the net electric field at the origin due to these two point charges.
00:33
So firstly, you have to figure out the distance of q1 from the origin, which is r1.
00:39
And r1 is going to be equal to the square root of 0 .6 squared plus 0 .8 squared, which equals 1.
00:53
Now we have to find r2.
00:55
So we're now looking for the point charge r2.
01:04
So that is just equal to 0 .6.
01:08
So in order to find the electric field due to q1, so e1, we can use the formula q1 over r squared.
01:20
So that becomes the coulomb constant, which is 9 times 10 to the 9, multiplied by 4 times 10 to the negative 9, divided by 1 squared.
01:40
And that is 36.
01:42
36.
01:48
So let's find the component of e1 along the x -axis.
01:55
So let's just call this e1...