Question
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$$$(5,-12)$$
Step 1
We know that $r$ is equal to the square root of $x^2 + y^2$. Given the point $(5,-12)$, we can substitute $x = 5$ and $y = -12$ into the equation. So, we get $r = \sqrt{5^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13$. Show more…
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