Question
a point on the terminal side of an angle $\theta$ in standard position is given. Find the exact value of each of the six trigonometric functions of $\theta .$$$(2,-3)$$
Step 1
The point is $(2,-3)$. We can use these coordinates to find the radius $r$ using the formula $r = \sqrt{x^2 + y^2}$. So, $r = \sqrt{2^2 + (-3)^2} = \sqrt{4 + 9} = \sqrt{13}$. Show more…
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