Question
A point $P$ lying inside the curve $y=\sqrt{2 a x-x^{2}}$ is moving such that its shortest distance from the curve at any position is greater than its distance from $X$ -axis. The point $P$ enclose a region whose area is equal to(a) $\frac{\pi a^{2}}{2}$(b) $\frac{a^{2}}{3}$(c) $\frac{2 a^{2}}{3}$(d) $\left(\frac{3 \pi-4}{6}\right) a^{2}$
Step 1
Step 1: Given the curve $y=\sqrt{2 a x-x^{2}}$, we can rewrite it as $x^{2}+y^{2}=2ax$ or $(x-a)^{2}+y^{2}=a^{2}$, which is the equation of a circle with center at $(a,0)$ and radius $a$. Show more…
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