Question
A point source of light $S$ is placed in front of a perfectly reflecting mirror as shown in the figure. $S^{\prime}$ is a screen. The intensity at the centre of the screen is found to be $I$. If the mirror is removed then the intensity at the centre of the screen would be(a) $I$(b) $\frac{10 I}{9}$(c) $\frac{9 I}{10}$(d) $2 I$
Step 1
Step 1: The intensity of light at the screen due to the direct point source $S$ is given by $I_1 = \frac{K}{a^2}$, where $K$ is a constant and $a$ is the distance from the source to the screen. Show more…
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