Question
A pole-vaulter just clears the bar at $5.80 \mathrm{m}$ and falls back to the ground. The change in the vaulter's potential energy during the fall is $-3.70 \times 10^{3} \mathrm{J} .$ What is his weight?
Step 1
70 \times 10^{3} \mathrm{J}$. The change in potential energy is given by the formula $\Delta PE = PE_{final} - PE_{initial}$. Show more…
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