From the graph, we can see that at $t=1.5s$, the position is $8m$ and at $t=4.0s$, the position is $-2m$. So, the change in position is $-2m - 8m = -10m$. The change in time is $4.0s - 1.5s = 2.5s$. Therefore, the average velocity is $\frac{-10m}{2.5s} = -4m/s$.
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