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A positive number $\epsilon$ and the limit $L$ of a function $f$ at $-\infty$ are given. Find a negative number $N$ such that $|f(x)-L|<\epsilon$ if $x<N$.$$\lim _{x \rightarrow-\infty} \frac{1}{x+2}=0 ; \epsilon=0.005$$
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Calculus 1 / AB
Chapter 1
LIMITS AND CONTINUITY
Section 4
Limits (Discussed More Rigorously)
Functions
Limits
Continuous Functions
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Lectures
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In mathematics, precalculu…
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$\lim _{x \rightarrow 2 \a…
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Limits Evaluate the follow…
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Suppose $ f $ is a positiv…
problem Number 45. Assume that X is one of them. Negative tools weren't over Exit plus two. It is one of that more point away. Five. So negative one over X plus two. It's more than open or five, where X Plus two is negative. Ah, so, um, one over X plus two is bigger than negative, open or fine, so x A plus two is smaller than negative. One over ballpoint or five years negative. 200 so X It's water than negative 100 to so we can say that n it's negative.
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