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A positive number $\epsilon$ and the limit $L$ of a function $f$ at $-\infty$ are given. Find a negative number $N$ such that $|f(x)-L|<\epsilon$ if $x<N$.$$\lim _{x \rightarrow-\infty} \frac{1}{x+2}=0 ; \epsilon=0.005$$

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Calculus 1 / AB

Chapter 1

LIMITS AND CONTINUITY

Section 4

Limits (Discussed More Rigorously)

Functions

Limits

Continuous Functions

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Lectures

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In mathematics, precalculu…

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In mathematics, a function…

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A positive number $\epsilo…

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03:54

$\lim _{x \rightarrow 2 \a…

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Limits Evaluate the follow…

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Suppose $ f $ is a positiv…

problem Number 45. Assume that X is one of them. Negative tools weren't over Exit plus two. It is one of that more point away. Five. So negative one over X plus two. It's more than open or five, where X Plus two is negative. Ah, so, um, one over X plus two is bigger than negative, open or fine, so x A plus two is smaller than negative. One over ballpoint or five years negative. 200 so X It's water than negative 100 to so we can say that n it's negative.

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