Question
A positron with a kinetic energy of $2.000$ MeV collides with an electron at rest and the two particles are annihilated. Two photons are produced; one moves in the same direction as the incoming positron and the other mowes in the opposite direction. Find the energies of the photons.
Step 1
The kinetic energy of the positron is given as $2.000$ MeV and the rest mass energy of the positron (which is the same as that of an electron) is $0.511$ MeV. So, the total energy of the positron is $E = 2.000 + 0.511 = 2.511$ MeV. Show more…
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A positron with a kinetic energy of 2.000 MeV collides with an electron at rest and the two particles are annihilated. Two photons are produced; one moves in the same direction as the in-coming positron and the other moves in the opposite direction. Find the energies of the photons.
A positron with a kinetic energy of 2MeV (mega electron-volt) collides with an electron at rest. The two particles are annihilated producing two photons. Find the energies of these photons assuming they move along the same direction as the initial positron (one in the same and the other in the opposite direction).
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