00:01
All right guys, so we're looking for to figure out the temperature that is on the lower part, which is the part that attached the stove.
00:08
Okay, if we draw a picture, so this is the pot, okay, and there's a stove heating up, this is the fire, okay? that's the lower part we're looking for.
00:24
Okay, so for this kind of question, we can set out such an equation, which is h equal to k -a times th minus tc over l.
00:40
H is the heat currents, k is the thermoconductivity of the steel, a is the surface area, thh is the higher temperature, tc is the lower temperature, and l is the length, and in this case the thickness of the parts.
00:57
Okay, so we know that the thickness of the part is 8 .5 millimeter, which is a.
01:12
5 times 10 to the power of 93 meter.
01:17
Okay.
01:21
And th is the one we're looking for.
01:26
Because the temperature at a low part of the slope is obviously higher than a temperature inside of the pots because it touched the stove directly.
01:36
So we know the tc is equal to, so the low temperature is equal to 100 degrees celsius.
01:44
That's the temperature inside of our parts.
01:46
Okay.
01:49
Area is 0 .15 meter square.
01:58
Okay.
02:02
And the thermoconductivity is equal to 50 .2 watts per meter times kelvin.
02:17
Well, it seems that we don't know the heat currents, but the heat currents are simply the power, which is equal to the energy divide by time.
02:32
Okay.
02:34
So the energy we are using here, is actually the heat that was used to boil water...