00:01
So for the first part of this question, we need to appreciate that accepting the null hypothesis and letting the process continue to run when actually overfilling or underfilling exists.
00:12
That's what is going to give us the errors.
00:15
Now, looking at the second part, so we reject h0, the null hypothesis, if our z is less than or equal to negative 1 .96, or if our z is greater than positive, 1 .96.
00:30
So if we look at negative 1 .96 and positive 96, these are four set values.
00:39
The corresponding x bar values, this would be 15 .71 and this would be 16 .2.
00:54
Now if we look at a mean value that is 16 .5, we are looking at a set that is equal to negative.
01:02
1 .44.
01:05
Recall that z is calculated from x -par minus mu -not divided by sigma divided by the square root of n.
01:16
For this z we are looking at a beta value that is equal to 0 .0749...