00:01
So for this problem, we can follow along with the hints that the question gives us.
00:05
First, we can use the escape velocity formula, which is v -escape is equal to square root of 2g times the mass of the body that you're orbiting, or that you're currently on, divided by the distance between the two objects.
00:24
Using the mass of the sun and the distance from the sun, you get that for an object at the earth's distance away from the sun, the earth's distance away from the sun, escape velocity would be equal to about 42 ,000, or to be exact, 41 ,900 and 90 meters per second.
00:46
And so now we're going to do the second part and transform that speed into the earth's reference frame.
00:51
So the earth is moving at some speed 2 pi r, which is the same r from here, divided by t, where t is equal to one year.
01:06
So the velocity of the earth as it's orbiting the sun is equal to 30 ,298 meters per second.
01:19
So if this is the speed that the earth is already traveling at as it orbits the sun, then technically you only need to launch an object.
01:29
The object's escape velocity being launched from the earth is just going to be v escape minus v, which is equal to 11 ,692 meters per second.
01:49
Now, lastly, we need to find how fast a projectile must be launched in order to have this speed when it's far from earth...