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# A proton accelerates from rest in a uniform clectric ficld of 640 . N/C. At some later time, its speed is $1.20 \times 10^{6} \mathrm{m} / \mathrm{s}$ . (a) Find the magnitude of the acceleration of the proton. (b) How long does it take the proton to reach this speed? (c) How far has it moved in that interval? (d) What is its kinetic energy at the later time?

## a. $6.12 \times 10^{10} \mathrm{m} / \mathrm{s}^{2}$b. 19.6$\mu \mathrm{s}$c. 11.8 $\mathrm{m}$d. $1.20 \times 10^{-15} J$

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##### Andy C.

University of Michigan - Ann Arbor

##### Aspen F.

University of Sheffield

##### Jared E.

University of Winnipeg

### Video Transcript

the magnitude of acceleration off. A problem is given by Newton's second law. That is, explosion is a force acting on a problem divided by the mass of our problem. Four series A Q times electric field divided by mass of the proton, our source of student rallies. Work you Andy. 1.6 times don't have power minus 19 times 6 40 Divided by the mass of the problem, which is 1.67 time. Stand to borrow minus 27 kg. This gives us an acceleration off 6.12 times 10 hour, 10 meter or second square. This is the acceleration of the probable, but be than the time taken will be cool. Thio Delta three. Divided by acceleration So Delta V. We have is 1.20 times till our six divided by exploration, which we just found 6.12 times gentle power 10. And if you find this gives us the time off for 1.96 times dental power minus five seconds, which is equal to 19.6 microseconds. What see the distance traveled? We're using a new tune, Equation of Motion that his Health X will be called the final velocity squared minus initial elastics were divided by two times off exploration initial lost a zero. So the final lost we have is one point to old times Duncan power six um, swearing it by the Ciro derided by exploration, sometimes off exploration which we just found this 16 point 12 times 10 to power tin Ah syn trying. This gives us a distance off 11.8 region the final kind of energy. Okay, f will be cool too. One of what? To Moscow for profit on dives, Their final lawsuit from problems so substituting values one or two massive proponents 1.67 times tended bar minus 27 kg times lost eve which is one from two old times two on our six whole square. This gives us there while dying take energy just one point to old times 10 to the power minus 15. Jules

Wesleyan University
##### Andy C.

University of Michigan - Ann Arbor

##### Aspen F.

University of Sheffield

##### Jared E.

University of Winnipeg