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Everyone.
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This is question number 23 from chapter 21 this problem.
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We're given that we have a proton placed in the uniform electric field and were given the magnitude of the field 2.75 times, 10 to the third newtons.
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Per cool homes were asked to find a the magnitude of the electrical force by the felt by the proton be the proton acceleration and see the proton speed after one microsecond in the field and it starts from rest.
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So let's start with part a.
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Here, um, we have our equation that we can use because we're given the strength of the electric field and that is f equals.
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Q r charge times e, which is our electric field.
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So we have both of those values.
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We can go ahead and plug them into find value for the force.
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So we have charge of a proton 1.6 times 10 to the minus 19th cool arms and then we have our strength of our electric field, which is 2.75 times 10 to the third newton per qualms, and that's going to give us a force equal to 4.4 times 10 to the minus 16.
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Nunes.
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Ok, so that's our answer for part a and we could move on apart.
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Be protons.
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Acceleration...