Question
A proton moves eastward in the plane of Earth's magnetic equator so that its distance from the ground remains constant. What is the speed of the proton if Earth's magnetic field points north and has a magnitude of $5.0 \times 10^{-5} \mathrm{T}$
Step 1
Therefore, the magnetic force on the proton is given by the equation $F_{m} = QvB$, where $Q$ is the charge of the proton, $v$ is the velocity of the proton, and $B$ is the magnitude of the magnetic field. Show more…
Show all steps
Your feedback will help us improve your experience
Suzanne W. and 87 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
see Sample Problem $A$. A proton moves eastward in the plane of Earth's magnetic equator, where Earth's magnetic field points north and has a magnitude of $5.0 \times 10^{-5}$ T. What velocity must the proton have for the magnetic force to just cancel the gravitational force?
At a certain location, the horizontal component of the earth's magnetic field is $2.5 \times 10^{-5} \mathrm{T},$ due north. A proton moves eastward with just the right speed for the magnetic force on it to balance its weight. Find the speed of the proton.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD