A proton moving perpendicular to a magnetic field of...

A proton moving perpendicular to a magnetic field of strength 3.5 mT experiences a force due to the field of $4.5 \times 10^{-21} \mathrm{N} .$ Calculate the following: a. the speed of the proton b. the kinetic energy of the proton Recall that a proton has a charge of $1.60 \times 10^{-19} \mathrm{C}$ and a mass of $1.67 \times 10^{-27} \mathrm{kg}.$

A proton moving perpendicular to a magnetic field of strength 3.5 mT experiences a force due to the field of $4.5 \times 10^{-21} \mathrm{N} .$ Calculate the following:
a. the speed of the proton
b. the kinetic energy of the proton Recall that a proton has a charge of $1.60 \times 10^{-19} \mathrm{C}$ and a mass of $1.67 \times 10^{-27} \mathrm{kg}.$

Key Concepts

Kinetic Energy

Kinetic energy is the energy possessed by an object due to its motion. For a particle with mass m moving at a speed v, the kinetic energy is given by the formula KE = 1/2 mv². This concept is fundamental in physics, describing how the motion of objects contributes to their total energy.

Lorentz Force

The Lorentz force is the force experienced by a charged particle moving in a magnetic field. It is calculated using the formula F = qvB sin(?), where q is the particle's charge, v is its velocity, B is the magnetic field strength, and ? is the angle between the velocity and the magnetic field. In situations where the particle moves perpendicular to the field (? = 90°), the sine term is unity, and the force simplifies to F = qvB.

Transcript

00:01 All right, guys.

00:03 Just have to clear this up in one second.

00:06 All right, cool.

00:09 So the question is a proton moving perpendicular to a magnetic field of strength, 3 .5 million tesla.

00:16 Experiences are forced due to the field of 4 .5 turns turn to 10 % per centaur negative between 1 newton.

00:22 Calculate the following a, the speed of the proton, and b, the kinetic energy of the proton.

00:29 Record that a proton has a charge of 1 .60 times turn 10 columns and a mass of 1 .67 times turner to power of 27 kg.

00:44 All right, so we've been given the parameters to take notes of.

00:50 It's time to go into our calculation.

00:55 So we have to record the magnitude of magnetic field equation, which is f, and the number.

01:04 Is equal to bvq or bq either way.

01:15 It's still the same thing.

01:18 Oh, yeah.

01:19 And b has been given as 3 .5 millesla.

01:47 3 .5, 3 .5 milles tesla.

01:57 And which converts into tesla, you would have to multiply by 0 .0.

02:05 0 .001 which would give you on 0 .0 .0 .035 tesla.

02:28 I just have to i don't know why i decided to do that for yet 0 .0035 tesla and now we go into the oh yeah and v is unknown.

03:06 Yeah, v is unknown.

03:08 Is v stands for speed because v stands for speed so v is unknown and q is given q stands for the chart of the proton is given as 1 .60 times 10 versus power negative 19 so now putting all that into the equation and making v the subject of formula we have v equals f divided by, in solving physics equations, i prefer to sort of like state out the parameters...

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