Question
A proton passes through a slit that has a width of $10^{-10} \mathrm{m}$. What uncertainty does this introduce in the momentum of the proton at right angles to the slit?
Step 1
This is given by half the width of the slit, which is $10^{-10} \mathrm{m}$. Therefore, $\Delta x = \frac{1}{2} \times 10^{-10} \mathrm{m} = 5 \times 10^{-11} \mathrm{m}$. Show more…
Show all steps
Your feedback will help us improve your experience
Jheremiah Simon and 64 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
An electron passes through a slit of width $1.0 \times 10^{-8} \mathrm{m}$ What is the uncertainty in the electron's momentum component in the direction perpendicular to the slit but in the plane containing the slit?
A proton has momentum 10 -20 N s and the uncertainty in the position of the proton is 10 -10 m. What is the minimum fractional uncertainty in the momentum of this proton?
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD