E.}{m_p c^2} + 1$, where $K.E.$ is the kinetic energy, $m_p$ is the rest mass energy of the proton, and $c$ is the speed of light. Substituting the given values, we get $\gamma = \frac{500 \times 10^9 eV}{938.3 \times 10^6 eV} + 1 = 533.9$.
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