The equation is given as:
\[-gH_A = \frac{fLQ_A^2}{2D} + \frac{fL_eQ_A^2}{2D} + \frac{KQ_A^2}{2g} - gH_{pump}\]
where $H_A$ is 70 ft, $L_e/D$ is due to the standard T branch and a standard elbow to be 60 and 30 respectively, and $K$ is 1.5 for entrance and exit.
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