Question

A quick-return mechanism is to be designed where the outward stroke consumes $t_1$ and the return stroke $t_2$. Determine the time ratio, imbalance angle, and speed at which the mechanism should be driven. $t_1=1.1 \mathrm{~s} ; t_2=0.8 \mathrm{~s}$.

   A quick-return mechanism is to be designed where the outward stroke consumes $t_1$ and the return stroke $t_2$. Determine the time ratio, imbalance angle, and speed at which the mechanism should be driven.
$t_1=1.1 \mathrm{~s} ; t_2=0.8 \mathrm{~s}$.
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Machines and mechanisms : Applied Kinematic Analysis
Machines and mechanisms : Applied Kinematic Analysis
David H Myszka 4th Edition
Chapter 5, Problem 1 ↓

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The time ratio \( R \) is defined as the ratio of the time taken for the outward stroke \( t_1 \) to the time taken for the return stroke \( t_2 \). \[ R = \frac{t_1}{t_2} = \frac{1.1 \, \text{s}}{0.8 \, \text{s}} = 1.375 \]  Show more…

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A quick-return mechanism is to be designed where the outward stroke consumes $t_1$ and the return stroke $t_2$. Determine the time ratio, imbalance angle, and speed at which the mechanism should be driven. $t_1=1.1 \mathrm{~s} ; t_2=0.8 \mathrm{~s}$.
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