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A rabbit is moving in the positive $x$ -direction at 2.00 $\mathrm{m} / \mathrm{s}$ when it spots a predator and accelerates to a velocity of 12.0 $\mathrm{m} / \mathrm{s}$ along the negative $y$ -axis, all in 1.50 $\mathrm{s}$ . Determine (a) the $x$ -component and (b) the $y$ -component of the rabbit's acceleration.

(a) $a _ { x } = - 1.33 \mathrm { m } \mathrm { s } ^ { - 2 }$

(b) $a _ { y } = - 8 \mathrm { ms } ^ { - 2 }$

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say that the app for part for the brother there is for the first part. Essentially we can save the average acceleration in the ex direction would be equal in the change in the velocity of the extraction divided by the change in time. This would be negative 2.0 meters per second from rather in that time interval of 1.50 seconds. This is equaling negative 1.33 repeating meters per second squared. We can then say that the average velocity in the why direction would be the change in velocity average acceleration in the UAE direction would be the change in velocity, the one direction divided by Delta T. And this is equally 12.0 meters per second and then this is divided by again 1.50 seconds and this is equaling 8.0 meters per second squared. This would be your answer and for the why component and the X component that is the end of the solution. Thank you for watching