A raindrop falls through a cloud, increasing in size as it picks up moisture. Assume that the rate of increase of its volume with respect to distance fallen is proportional to the cross-sectional area of the drop at any time (that is, the mass increase $d m=\rho d V$ is proportional to the volume $\pi r^{2} d y$ swept out by the drop as it falls a distance $d y$ ). Show that the radius $r$ of the drop is proportional to the distance $y$ the drop has fallen if $r=0$ when $y=0$. Recall that when $m$ is not constant, Newton's second law is properly stated as $(d / d t)(m \tau)=F$. Use this equation to find the distance $y$ which the drop falls in time $t$ under the force of gravity, if $y=\dot{y}=0$ at $t=0 .$ Show that the acceleration of the drop is $g / 7$ where $g$ is the acceleration of gravity.