Question
A raindrop inside a thundercloud has charge $-8 e$. What is the electric force on the raindrop if the electric field at its location (due to other charges in the cloud) has magnitude $2.0 \times 10^{6} \mathrm{~N} / \mathrm{C}$ and is directed upward?
Step 1
We know the charge of the raindrop, which is $-8e$. Since the elementary charge $e = 1.6 \times 10^{-19} \mathrm{C}$, the charge of the raindrop is $-8(1.6 \times 10^{-19}) \mathrm{C} = -12.8 \times 10^{-19} \mathrm{C}$. Show more…
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