Question
A random variable $X$ has a mean $p=12$, a variance $a^{2}=9,$ and an unknown probability distribution. Using Chebyshev's theorem, estimate(a) $P(6<X<18)$(b) $P(3<X<21)$.
Step 1
The standard deviation $\sigma$ is the square root of the variance, so $\sigma = \sqrt{9} = 3$. Show more…
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