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A ray of light is incident on the surface of a block of clear ice at an angle of $40.0^{\circ}$ with the normal. Part of the light is reflected, and part is refracted. Find the angle between the reflected and refracted light.
$\text { The angle between the reflected and transmitted light is } 110.59^{\circ}$
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University of Sheffield
we have a following situation. Well, here we have ice and this is air light. Strike the surface of the ice and reflects back and the angle off incident. This mixes that theta I reflected in all our some off light gets into the eye So it depends to worsen our movies is normal and it makes an angle loaf Oh ST T They're total angle from practically to the refracted me Here is also we call it so we are asked to find what is the oil for? In order to find Alfa, we know the reflecting ducks off ICI's or one point trees or nine on DA reflected in angle off incident is equal to the angle of refraction which is a 40 degrees. And we could write Snell's law from air to the ice that is, in one time scientist one physical to end two time signed data to where in one is equal to wanted and too easy call to end which is a call to one point 309 the refractory next off ice where better one is it called tau angle off incident which is a 40. Then, substituting those values we get assigned forties. He called the 1.309 times a sign off entity. This is a refracted angle. Then we find refracted angle to be signed in Warsaw for signed Foti, divided by 1.309 This gives us a factor. Angle off 29.41 Adi, please. Candle between refracted and transmitted uh, will be also that is 1 80 minus that t prostate are from the human figure Then our job is now to substitute the values for 30 which we found is 29.41 Angela Perfection is a 40 day excuse us all for for 110.59 59 degrees.