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A reaction has $\Delta H_{298}^{\circ}=100 \mathrm{kJ} / \mathrm{mol}$ and $\Delta S_{298}^{\mathrm{o}}=250 \mathrm{J} / \mathrm{mol}$ . Is the reaction spontaneous at room temperature? If not, under what temperature conditions will it become spontaneous?
The reaction is not spontaneous under room temperature.The reaction becomes spontaneous at 400 $\mathrm{K}$ .
Chemistry 102
Chapter 16
Thermodynamics
Drexel University
Brown University
University of Toronto
Lectures
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the spontaneity off. A reaction is calculated by the represented formula. Delta G is a control data H minus D Delta s hear Delta H is a changing and jalopy. Delta s is and Robbie change. He represents temperature and Delta G is change and gives free energy at standard conditions For the question the substitute 250 jewels for mole Kelvin for Delta is 100 kilo Jules formal for Delta H on DDE 2.98 four temperature in Calvin's substituting in the values we have standard Delta G equals 25.5 calo Jules formal. In this case, the Delta G value is greater than zero. So the reaction will be non spontaneous on the room temperature. The right and preacher for spontaneous reaction is also being calculated, substituting in the values we have them preachers should be above then 400 degree, 400 Kelvin for reaction. Toby. Spontaneous
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