A real number $a$ is called a cluster point of a sequence $\left(a_{n}\right)$ in $\mathbb{R}$ if there is a subsequence $\left(a_{n_{k}}\right)$ of $\left(a_{n}\right)$ such that $a_{n_{k}} \rightarrow a$
(i) Show that if $a_{n} \rightarrow a$, then $a$ is the only cluster point of $\left(a_{n}\right)$.
(ii) Show that the converse of (i) is not true. In other words, show that there is a divergent sequence that has a unique cluster point. (Hint:
$a_{2 k}:=\frac{1}{2 k}$ and $a_{2 k+1}:=2 k+1$ for $k \in \mathbb{N}$.)
(iii) Show that if $a_{n} \rightarrow \infty$ or if $a_{n} \rightarrow-\infty$, then $\left(a_{n}\right)$ has no cluster point.
(iv) Show that the converse of (iii) is not true. In other words, show that there is a sequence without a cluster point that neither tends to $\infty$ nor tends to $-\infty .$ (Hint: $a_{n}:=(-1)^{n} n$ for $n \in \mathbb{N}$.)