00:01
So we will be assuming that the mean number of times that males eat out is equal to the meal as females eating out who both live alone, and alternately that they're just different, and men and women.
00:17
And we have our male data.
00:21
We have our male data having a mean of 24 .51.
00:30
The standard deviation for that group is 4 .48, and our sample size for males is 35.
00:45
And for our women, for our females, and again, these are people who live alone, the mean number of time eating out is 22 .69.
00:57
And the standard deviation for those women was 3 .86, little smaller variability, and the sample size for women was 40.
01:08
Now, both of these sample sizes are greater than or equal to 30, so our textbook tells us it's okay to find a z value.
01:16
And we are using a 1 % significance level, so let's just quickly draw this little picture here of our critical value.
01:23
We're also asked to find, i think, the p value, but we would have, for a 1 % significance level, we would split the area to the two tails, so 0 .005.
01:35
And our critical values are 2 .576, or you might call it 2 .58, and this z value is negative 2 .576.
01:46
And so we would reject if we're this way or this way.
01:49
Well, we reject the null.
01:51
We would fail to reject the null if we're in between those values.
01:54
So let's find our z value.
01:57
Our z value or our test statistic is the difference between these two numbers, the 24 .51 minus the 22 .69.
02:07
And we're assuming that the difference between the two distributions is zero.
02:10
And then we're going to find that standard error where we're going to have to take the variance of each individual divided by the sample size...