Question
A recording engineer works in a soundproofed room that is $44.0 \mathrm{~dB}$ quieter than the outside. If the sound intensity in the room is $1.20 \times 10^{-10} \mathrm{~W} / \mathrm{m}^{2}$, what is the intensity outside?
Step 1
0 dB) and the intensity inside the room (I1 = 1.20 * 10^(-10) W/m²). We want to find the intensity outside the room (I2). We can rearrange the formula to solve for I2: I2 = I1 * 10^(ΔdB/10) Show more…
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A recording engineer works in a soundproofed room that is 44.0 $\mathrm{dB}$ quieter than the outside. If the sound intensity that leaks into the room is $1.20 \times 10^{-10} \mathrm{W} / \mathrm{m}^{2},$ what is the intensity outside?
A recording engineer is in a soundproof room that is 44 dB quieter than outside. If the sound intensity in the room is 1.2 * 10^-10 W/m^2, what is the intensity outside?
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