Question
A rectangular block having mass $\mathrm{m}$ and cross sectional area A is floating in a liquid having density $\rho$. If this block in its equilibrium position is given a small vertical displacement, its starts oscillating with periodic time $\mathrm{T}$. Then in this case $\ldots \ldots$(A) $\mathrm{T} \propto(1 / \sqrt{\mathrm{m}})$(B) $T \propto \sqrt{\rho}$(C) $\mathrm{T} \propto(1 / \sqrt{\mathrm{A}})$(D) $\mathrm{T} \propto(1 / \sqrt{\rho})$
Step 1
In this case, the volume of the block is given by $V = A \cdot h$, where $A$ is the cross-sectional area and $h$ is the height of the block. So, we can write $\rho = \frac{m}{A \cdot h}$. Show more…
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