Question
A red LED emits light at $0.1$ watt uniformly around it. The amplitude of the electric field of the light at a distance of $1 \mathrm{~m}$ from the diode is [2015](A) $2.45 \mathrm{~V} / \mathrm{m}$(B) $5.48 \mathrm{~V} / \mathrm{m}$(C) $7.75 \mathrm{~V} / \mathrm{m}$(D) $1.73 \mathrm{~V} / \mathrm{m}$
Step 1
Mathematically, this can be written as: \[I = \frac{1}{2} \varepsilon_0 c E^2\] where \(I\) is the intensity, \(\varepsilon_0\) is the absolute permittivity, \(c\) is the speed of light, and \(E\) is the electric field amplitude. Show more…
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