00:02
Part a, the enthalpy and entropy at state 1.
00:25
For given pressure and temperature, 200 kiosk, and temperature, 0 degrees celsius or 273 kelvin, using table a13, anthology is 253 .0 .07 kilojoules per kg, and entropy is, and entropy is, 0 .9699 kilo jude per kg.
01:20
Per kelvin isentropic enthalpy at state to for pressure 1400 kiosk and s2 is called to s one using table a 30 s2 s will be 295 .95 kilo jr per kage the actual anthology at state 2 using isentropic efficiency relation h2 is called to h1 plus s 2 s minus h1 now substitute the value h1 is 253 .07 plus 295 .955 .95 0 .95 minus 253 .107 upon 0 .88.
03:45
So it is 3001 .8 kilojoule per kg.
04:04
The enthalpy at third and fourth state is determined for saturated liquid at 48 degrees celsius temperature.
05:01
Is called to h3 is called to h 4 120 .43 kilojoule per the heating load is rate of flow of refrigerant into h1 minus h4 that is 0 .025 into 253 .07 minus 120 .41 so it is to be 3 303 3 .32 kilowatts the power is determined mass flow rate into h2 minus h1 .025 into 301 .8 minus 253 .07 that is 1 .22 kilowatt coefficient of performance will be heating load upon rate of doing the work 3 .32 upon 1 .22 that is 2 .72.
06:44
Now part b.
06:51
In this case, enthalpy and entropy and entropy for saturated paper at given pressure using table, 81, h1 having the value 240 .24 .5 kilojoules per kg...