00:01
We are given two resistors, r1 and r2, and that when they're connected to an emf of epsilon, they actually consume power of p1 and p2.
00:20
Now what we want to know is the total power consumed when they are both connected to the same source, but either in parallel or in series with this source.
00:31
So we started with the one in parallel.
00:32
When they're in parallel say this is our emf source, right, it's r1, r2, then they will both experience the same potential difference, which is epsilon, therefore the power displayed it would be given as v square over r, so it's just e square over r, it is similar to when they are just simply connected by themselves to the emf source.
01:04
And so no difference, right? it's just i, the power dissipated by the first resistor would just be our p1, the original p1, and this the new p1 is just equals to the original p1, the new p2 still equals to the original p2, and therefore the total power is just p1 plus p2.
01:31
No difference.
01:33
Now however if you have connected them in series, so now we have r1 and r2, now this is a different scenario.
01:54
So what we have to do is to first we want to find the power p...