From exercise 9, we have $x = \frac{\sqrt{2}}{2} x^{\prime} - \frac{\sqrt{2}}{2} y^{\prime}$ and $y = \frac{\sqrt{2}}{2} x^{\prime} + \frac{\sqrt{2}}{2} y^{\prime}$. Replacing the values of $x$ and $y$ in the given equation, we get:
\[3\left(\frac{\sqrt{2}}{2}
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