00:05
We're given a polynomial m, so m of t, which is t to be r plus a sub r minus 1, t to the r minus 1, plus all the way down to a1 times t plus a0.
00:26
I'm told that this is the minimal polynomial of an n -square -maid matrix, a, we're asked to prove statements about no polynomial.
00:47
So, in part a, we're asked to prove matrix a is non -sindular, if and only if the constant term of the polynomial, a0 is non -zero.
00:58
To derive this, we use several equivalent statements.
01:02
Well, we know that a is non -singular in previous exercises.
01:09
If and only if zero is not...
01:14
A root of our minimal polynomial and of t.
01:21
And this is true, if and only if the constant term, a zero is non -zero...