For oxygen, $R = 8314 \, \text{J/kg.K}$.
We can rearrange this equation to solve for the volume $V$:
\[V = \frac{mRT}{P}\]
Substituting the given values, we get:
\[V = \frac{1 \, \text{kg} \times 8314 \, \text{J/kg.K} \times 180 \, \text{K}}{40 \times 10^5 \,
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