00:01
So we're told a ring with a mass m is cut from a thin, uniform plate, and determine the mass moment of the ring with respect to the a -a -a -prime axis and the cc -prime axis, so this one and this one.
00:19
So to get this one, we're going to need this one.
00:22
But because of symmetry, we know this one is going to be the same as that one.
00:29
So we need to find area moments.
00:32
And so the area moment of this cross section, we can just look it up and then subtract out the hole.
00:39
So we get pi over 4, r2, the outer radius here to the fourth minus r1, the inner radius to the fourth.
00:47
And that also equals the area moment about this axis.
00:51
Now the area is pi times r squared minus r1 squared from the area here.
00:59
So the area of the total minus the cutout hole.
01:08
The mass is the density times the volume.
01:14
So we can write the, this is, so the mass moment is row t times the area moment, and row t is just the mass over the area, so the aerial density.
01:31
So we get this expression here...