00:01
Given in the question, a river flows with a uniform velocity v.
00:10
After traveling a distance d1 that is equal to 1 kilometers upstream, she passes a log floating by.
00:24
The boater continues to travel upstream for another time t equal to 60 minutes that is roughly 1 hour and then she returns downstream to her starting point.
00:48
The log and she reaches her starting point at the same time.
00:54
It has been asked to find the velocity of the river.
01:03
So let the velocity of the boat relative to the still water or ground be u.
01:21
Then the velocity of the boat upstream would be u minus v and the velocity of the boat downstream would be u plus v.
01:37
Now time taken to pass the log 1 kilometer away.
01:44
Time taken to pass the log 1 kilometer away.
01:47
Let's say it be represented by t1 that will be equal to d1 divided by u minus v because it is while moving upstream.
01:59
So it is 1 kilometer divided by u minus v.
02:04
This much hours.
02:06
Now distance traveled in another 60 minutes or 1 hour would be let's say d2 again in the upstream direction...