8 \mathrm{m/s^2}$), and $t$ is the time taken.
For the first $50 \mathrm{m}$, we have:
$50 = \frac{1}{2}(9.8)t^2$
Solving for $t$, we get:
$t^2 = \frac{100}{9.8}$
$t = \sqrt{\frac{100}{9.8}} \approx 3.2 \mathrm{s}$
So it takes about $3.2 \mathrm{s}$ to fall
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