00:02
In this question, we have a rocket that fires two engines, and one of the engines fires in the forward direction, so the right, 725 newtons.
00:11
The other engine fires at an angle of 32 .4 degrees at a force of 513 newtons, and we're looking for the resultant vector.
00:24
So we can sketch out these two vectors and put them tip to tail, so then our resultant vector.
00:32
Will be this vector that i'll call little r.
00:36
And to find the magnitude and direction of this vector, we need to know the x and y component.
00:42
And in order to solve for the x and y components of our resultant vector, we need to break up this second vector, the one pointed at 32 .4 degrees, into its components.
00:55
So you can see here that this is the right angle, and this angle here is our angle 32 .4 degrees.
01:01
So we can just use trace.
01:03
Define the x and y component.
01:06
So the y component would be 513 times the sign of the angle, so 513 sign 32 .4, and the x component will be the cosine, so 513 times cosine 32 .4.
01:25
So in the x direction you can see that we have 725 plus 513 times the cosine of 32 .4, which is equal to approximately 1 ,158 .14 newtons...