00:01
In this problem, we have a rocket that has an acceleration of 21 .5 meters per second squared, and it maintains its acceleration for a time of 8 .75 seconds.
00:16
So in part a, we want to find its final velocity after that time, and part b, we want to find how far did you travel.
00:25
So for part a, we can use the schematic equation, which is the final velocity.
00:31
Is equal to initial velocity plus acceleration times time.
00:37
Now here the rocket is starting at rest, so the initial velocity is zero, and we have acceleration, we have time, so we just plug those in, and we can get the final velocity of rocket.
00:49
Now, part b, to find the distance traveled, we can use another kinematic equation, which is x, the distance travel is equal to initial velocity times time, plus one -half, acceleration times t squared.
01:06
And again, initial velocity is zero.
01:08
So we're left with one half times a times t squared...