Question
A rod with density $\delta(x)=2+\sin x$ lies on the $x$ -axis between $x=0$ and $x=\pi .$ Find the center of mass of the rod.
Step 1
The mass of the rod is given by the integral of the density function over the interval from 0 to $\pi$. So, we have: \[M = \int_{0}^{\pi} \delta(x) \, dx = \int_{0}^{\pi} (2 + \sin x) \, dx.\] Show more…
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