Question
A roller coaster reaches the top of the steepest hill with aspeed of 6.0 $\mathrm{km} / \mathrm{h}$ . It then descends the hill, which is at anaverage angle of $45^{\circ}$ and is 45.0 $\mathrm{m}$ long. What will itsspeed be when it reaches the bottom? Assume $\mu_{\mathrm{k}}=0.12$ .
Step 1
Let's denote the initial velocity as $V_0$. So, $V_0 = 6.0 \, \text{km/h} \times \frac{1 \, \text{m/s}}{3.6 \, \text{km/h}} = 1.667 \, \text{m/s}$. Show more…
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A roller coaster reaches the top of the steepest hill with a speed of 6.0 km/h It then descends the hill, which is at an average angle of 45$^\circ$ and is 45.0 m long. What will its speed be when it reaches the bottom? Assume $\mu_k=$ 0.12.
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