0:00
16 .52.
00:01
So we've got a rope that's under a tension of 200 newtons and it's fixed at both ends.
00:06
We're told that it's oscillating in its second harmonic pattern for the standing wave.
00:12
Now we're given the function for the displacement and we'd like to find out some things about this rope.
00:19
Like we want to find its length, the wave speed, the mass of the rope, and then what the period is of the third harmonic standing wave pattern.
00:33
So first, for the second harmonic, we know that we're going to fit two half -wave lengths in.
00:48
Because for a string that's fixed at both ends, the number of the harmonic is the number of half -wave lengths.
00:57
So the wavelength is just going to be the overall length of the rope.
01:02
The frequency, as we know, is the speed divided by the length.
01:08
It's the speed divided by the wavelength, but in this case it's just the length of the rope.
01:12
So here we can see that the wave number is pi over two radians per meter.
01:29
We know the wave number is also equal to 2 pi divided by the wavelength, and we know that the wavelength is the length of the rope.
01:44
So then just rearranging this for l, we find that the length of the rope is 4 meters.
02:00
Now we know omega from this is 12 pi radians per second, which is also 2 pi -f.
02:16
We could in fact just divide the, you know what, actually let's just think of it that way...