0:00
Hello.
00:01
So here we found the proportion of the students who preferred beer brand a in the blind test with 0.5.
00:07
So we have that p is going to be equal to 0.5.
00:11
And then in part they were considering a random sample of 100 students from this college.
00:16
Um and we're interested in computing the probability that more than 60% of the students from this sample preferred brand eight.
00:24
So to calculate the probability that p hat is greater than 0.6.
00:28
So we have the sample proportion is p hat has a normal distribution with mean mu is equal to p which is equal to 0.5.
00:36
Therefore the standard deviation sigma is going to be equal to the square root of p times one minus p.
00:43
All over ends, just to square root of 0.5 times 0.5.
00:47
All over 100 which is going to be equal to 0.5.
00:51
Um and then for our probability that's going to be equal to one minus the probability that z is less than equal to 0.6 minus 0.5 are divided by 0.5 is going to be equal to one minus the probability that z is less than equal to two, which is going to be equal to zero 0.228.
01:15
So we have that the probability that more than 60% of the students from this sample have preferred on the brand is going to be equal to 0.0 2 to 8.
01:28
And then in part b we want to compute the probability that were between 45% and 60%...